Question

Differential equations:

y' = y(3 − ty)
Describe how solutions appear to behave as t increases and how their behavior depends on the initial value y0 ("0" is a subscript) when t = 0.

How do you solve this question? I don't think the equation is linear so I am confused as to how to solve it.. Can someone help me please?

Answer 1

y' = y(3 - ty)
y(t) = 9e^(3t) / (c1 + e^(3t)(3t - 1))

As t increases, y(t) reduces