asked 95.4k views
1 vote
Approximate to the nearest tenth the real zeros of f(x) = –5x3 + 9x2 + 12x + 2.

answers:
The zeros are approximately 0.2, 0.7, and 2.7.
The zeros are approximately –2.7, –1.7, and 0.2.
The zeros are approximately –0.2, –0.7, and 2.7.
The zeros are approximately –0.5, –0.7, and 1.7.

2 Answers

3 votes

Answer:

the answer is C

Explanation:

answered
User Rob Osborne
by
8.7k points
5 votes
Correct answer is C.


-5 x^3 + 9 x^2 +12 x+ 2=(-5 x-1) \left(x^2-2 x-2\right) \\ \\\left\{-(1)/(5),1-√(3),1+√(3)\right\}\to \{-0.2,-0.732051,2.73205\}

Or check if f(0.2) = 0 to eliminate A and B.
Then check if f(-0.5) = 0 to eliminate D.
answered
User Camilo Martin
by
7.9k points
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