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1 vote
The Ka of a monoprotic weak acid is 6.07 × 10-3. What is the percent ionization of a 0.179 M solution of this acid?

asked
User Hdkrgr
by
8.3k points

1 Answer

2 votes
What you need to do my friend is write the chemical equation of dissociation of your acid AH with water, with initial concentration co, then consider that a fraction α reacts with water. Concentration and Ka are big enough so that you can consider that
1−α≈1
Then write expression of Ka, then solve for α. You should find about 18.4% I hope this works really good for you
answered
User Ayyoudy
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8.0k points
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