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State the y-coordinate of the y-intercept for the function below. ƒ(x)=x^3-x^2-x+1 ...?

State the y-coordinate of the y-intercept for the function below. ƒ(x)=x^3-x^2-x+1 ...?
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State the y-coordinate of the y-intercept for the function below.

ƒ(x)=x^3-x^2-x+1 ...?

asked
User Salim Khan
by
8.0k points

2 Answers

1 vote

Answer:

1

Explanation:

Answer is 1 for Apex Precal

answered
User Flyingace
by
7.9k points
5 votes
when y intercpets, x = 0
so here,

ƒ(x)=x^3-x^2-x+1
ƒ(x)=(0)^3-(0)^2-0+1
ƒ(x)= +1
answered
User Noam Manos
by
7.3k points
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