Find the limit 3/x^2-6x+9 as x approaches 3 ...?

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asked May 2, 2017 50.2k views

1 Answer

Lauri Harpf · Answer 1 · 2017-05-06T18:33:34+0000

Lim [3 / (x^2 - 6x + 9)] = Lim [3 / (x -3)^2] ...(by factoring)

Find the side limits:

x -->3 + => Lim [3 / (x -3)^2] = 3/0 = ∞

x -->3 - => Lim [3 / (x -3)^2] = 3/0 = ∞

Then the limit is ∞

Find the limit 3/x^2-6x+9 as x approaches 3 ...?

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