What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=12-x^2?

Question

asked Nov 22, 2017 167k views

1 Answer

TRose · Answer 1 · 2017-11-27T02:23:13+0000

Area of rectangle: LxW
so
(2x)(y)=2x(12-X^2)
then I would solve for x and substitute it back into the Area equation.

This is your area equation:
A =2x(12-x^2)
maximize by differentiating and setting equal to 0 then solve for x.

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=12-x^2?

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions