What is missing is the density of salt water. Let's denote it ρ. 
The pressure at depth d then is: 
p = p0 + ρ g d 
, where p0 is the atmospheric pressure at the surface of the sea. We assume it is equal to the 1 atm inside the sub. 
Hence the pressure difference between inside and outside of the window is: 
Δp = ρ g d 
The force on the window is this pressure difference, multiplied by the area of the circular window of diameter D. The latter equals 
A = ¼ π D². 
So 
F = p A = ¼ π D ²ρ g d. 
This should be less than Fmax. 
Hence d < Fmax / (¼ π D ²ρ g ).