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Find the limit. lim (x-5)/((x^2)-25) x-> 5+

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User Wollnyst
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1 Answer

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\lim_(x \to 5) (x-5)/( x^(2) -25) =( (0)/(0) ) = \\ =\lim_(x \to 5) (x-5)/((x-5)(x+5))= \\ =\lim_(x \to 5) (1)/(x+5)= \\ = (1)/(5+5)= (1)/(10) = 0.1
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User PyRsquared
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