Question

S=2(lw+lh+wh) solve for w

Answer 1

`S=2(lw+lh+wh)\\ S=2lw+2lh+2wh\\ S=w(2l+2h)+2lh\\ w(2l+2h)=S-2lh\\ w=(S-2lh)/(2l+2h)`

Answer 2

we have

`s=2(lw+lh+wh)`

Solve for w means that clear variable w

`s=2(lw+lh+wh)\\s=2lw+2lh+2wh`

Group terms that contain the variable w, and move the other terms to the opposite side of the equation

`(s-2lh)=(2lw+2wh)`

Factor the variable w

`(s-2lh)=w(2l+2h)`

Divide both sides by
`(2l+2h)`

`(s-2lh)/(2l+2h)=w(2l+2h)/(2l+2h)`

`w=(s-2lh)/(2l+2h)`

therefore

the answer is

`w=(s-2lh)/(2l+2h)`