Question

Select the atoms whose ions have an electron configuration of nd5(n = 3, 4, 5 ...). For example, the 2+ ion for V ends the electron configuration with 3d 3.

Ir
Rn
Fe
Pa
Y
Re

Answer 1

Ir = [Xe] 4f14 5d7 6s2
Rn = [Xe] 4f14 5d10 6s2 6p6
Fe = [Ar] 3d6 4s2
Pa = [Rn] 5f2 6d1 7s2
Y = [Kr] 4d1 5s2
Re = [Xe] 4f14 5d5 6s2
So only Rhenium (Re) has an electronic configuration where the d orbital has 5 electrons in it.

Answer 2

Answer: The atoms whose ions have electronic configuration as
`nd^5` are Iridium (Ir), Iron (Fe) and Rhenium (Re)

Step-by-step explanation:

An ion is formed when a neutral atom looses or gains electrons.

• When an atom looses electrons, it results in the formation of positive ion known as cation.
• When an atom gains electrons, it results in the formation of negative ion known as anion.

For the given elements:

Iridium: The electronic configuration of this element is
`[Xe]6s^25d^7`. The stable oxidation state of iridium is +4.

The electronic configuration of
`Ir^(4+)` is
`[Xe]5d^5`

Radon: The electronic configuration of this element is
`[Xe]6s^25d^(10)6p^6`. This is a stable element.

Iron: The electronic configuration of this element is
`[Ar]4s^23d^6`. The stable oxidation state of iron is +3.

The electronic configuration of
`Fe^(3+)` is
`[Ar]3d^5`

Protactinium: The electronic configuration of this element is
`[Rn]7s^26d^15f^2`. The stable oxidation state of protactinium is +3.

The electronic configuration of
`Pa^(3+)` is
`[Rn]7s^2`

Ytterium: The electronic configuration of this element is
`[Kr]5s^24d^1`. The stable oxidation state of ytterium is +3.

The electronic configuration of
`Y^(3+)` is
`[Ar]4s^23d^(10)4p^6`

Rhenium: The electronic configuration of this element is
`[Xe]6s^25d^5`. The stable oxidation state of rhenium is +2.

The electronic configuration of
`Re^(2+)` is
`[Xe]5d^5`

Hence, the atoms whose ions have electronic configuration as
`nd^5` are Iridium (Ir), Iron (Fe) and Rhenium (Re)