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Is y=112(1.32)^x expotential growth or decay?

Is y=112(1.32)^x expotential growth or decay?
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Is y=112(1.32)^x expotential growth or decay?

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User Wrokar
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1 Answer

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growth because you're multiplying with a number higher than 1. if the equation was y=112(0.32)^x, then it is decay.
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User Jchavannes
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