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Find the standard form of the equation of the parabola with vertex at the origin focus (-2,0)

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User Katona
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1 Answer

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vertex = (0, 0)
focus = (-2, 0)
p = -2 - 0 = -2
Required equation is (y - k)^2 = 4p(x - h); where (h, k) = (0, 0), the vertex
(y - 0)^2 = 4(-2)(x - 0)
y^2 = -8x

Required equation in standard form is x = -1/8 y^2
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User Velidan
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