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5 votes
Solve k^2 + 13k + 30 = 0

asked
User Shuwen
by
7.9k points

2 Answers

1 vote
If you are using the quadratic equation to find k then the answers will be k=-3 and k=10.
answered
User Caladan
by
7.6k points
5 votes
Simplifying k2 + 13k + 30 = 0 Reorder the terms: 30 + 13k + k2 = 0 Solving 30 + 13k + k2 = 0 Solving for variable 'k'. Factor a trinomial. (10 + k)(3 + k) = 0 Subproblem 1Set the factor '(10 + k)' equal to zero and attempt to solve: Simplifying 10 + k = 0 Solving 10 + k = 0 Move all terms containing k to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + k = 0 + -10 Combine like terms: 10 + -10 = 0 0 + k = 0 + -10 k = 0 + -10 Combine like terms: 0 + -10 = -10 k = -10 Simplifying k = -10 Subproblem 2Set the factor '(3 + k)' equal to zero and attempt to solve: Simplifying 3 + k = 0 Solving 3 + k = 0 Move all terms containing k to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + k = 0 + -3 Combine like terms: 3 + -3 = 0 0 + k = 0 + -3 k = 0 + -3 Combine like terms: 0 + -3 = -3 k = -3 Simplifying k = -3Solutionk = {-10, -3}
answered
User Atiq
by
8.6k points
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