Solve 5x + 7 ≥ 2 (just putting this here since the question is too short)

asked Oct 23, 2017 135k views

4 votes

Solve 5x + 7 ≥ 2

(just putting this here since the question is too short)

by Aury

8.2k points

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7 votes

5x + 7 ≥ 2
- 7 -7
5x ≥ -5
/5 /5
"x ≥ -1" is your final answer

Bas Swinckels answered Oct 25, 2017

8.4k points

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2 votes

1.
$5x + 7 \geq 2$
2.
$5x \geq -5$
3.
$x \geq -1$

1. Start
2. Subtract 7 from both sides
3. Divide both sides by 5

Ivo Wetzel answered Oct 28, 2017

7.4k points

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