Question

An object accelerates to a velocity of 230m/s over a time of 2.5s. the acceleration it experienced was 42 m/s^2. what was its ital velocity?

Answer 1

Use the equation Vf=Vi+(A)(t)
since you're trying to find the initial velocity, rearrange the equation to say Vi=Vf-(A)(t)
so, Vi=230-(42)x(2.5)
final answer: Vi=125m/s

Answer 2

125m/s

Step-by-step explanation:

Using one of the equations of motion,

v = u + at

where

u = initial velocity of the object

v = final velocity of the object

=> v = 230m/s

a = acceleration of the object

=> a = 42m/
`s^(2)`

t = time taken for the acceleration

=> t = 2.5s

Substituting these values into the equation above gives

230 = u + 42(2.5)

Making u the subject of the formula gives;

u = 230 - 42(2.5)

u = 230 - 105

u = 125m/s

Therefore the initial velocity of the object was 125m/s

Note: The question erroneously has ital velocity rather than initial velocity. This has been corrected as there is no such thing as ital velocity.