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What is the solution set of the quadratic inequality 6x2+1<0

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User Gented
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2 Answers

3 votes
minus 1 from both sides
6x^2<-1
divide both sides by 6
x^2<-1/6
take the square root of both sides
x<√(-1/6)
x<i√(1/6)

the solution is i√(1/6)
if you only consider real number, the solution set is empty
answered
User Josh Hudnall
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7.8k points
3 votes

Answer:

Solution set of the quadratic equation is, Empty set

Explanation:

Given the quadratic equation:
6x^2+1>0

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract both sides by 1 we get;


6x^2+1-1>0-1

Simplify:


6x^2>-1

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by 6 we get;


(6x^2)/(6) >(-1)/(6)

Simplify:


x^2>(-1)/(6)

For any x in real number there does not exist any number x which satisfy


x^2>(-1)/(6) , therefore, there is no solution for this set of the quadratic inequality or in other word we can say that set of the solution is Empty set.

answered
User Dvsoukup
by
8.0k points

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