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Perpendicular line equation for (0,2); 3y-x=0

Perpendicular line equation for (0,2); 3y-x=0
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Perpendicular line equation for (0,2); 3y-x=0

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User Nikjohn
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8.6k points

1 Answer

4 votes
3y-x=0
3y=x
y=1/3x (slope)

(0,2)
y=1/3x+2
Above is the given line.
The perpendicular line containing point (0,2) would be y=-3+2
answered
User OLas
by
8.4k points
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