Question

What is the molarity of an aqueous solution that contains 12.2 grams of SrCl2 dissolved in 2,500 milliliters of solution?

Answer 1

0.031 M is the molarity of an aqueous solution that contains 12.2 grams of SrCl2 dissolved in 2,500 milliliters of solution.

Answer 2

Molarity is

mol
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Litre

First you need to find how many moles 12.2 grams is

To do this you need to find molecular weight of SrCl2
(87.62)+(35.45*2) = 158.52 g/mol

Now convert 12.2 g into moles
12.2 g * 1 mol / 158.52 g (12.2/158.52) = 0.0769618976 moles

Next convert 2500 mL into Litres
2500mL * 1L / 1000mL (2500/1000) = 2.5 Litres

Finally do moles / Litres

0.0769618976 / 2.5 = 0.0308 M