Question

Please help due ASAP
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Answer 1

Mid point M of CF will have coordinates,
x
M
=
x
C
+
x
F
2
=
3
+
9
2
=
6

y
M
=
y
C
+
y
F
2
=
4
+
8
2
=
6

Using distance formula,
Distance
¯¯¯¯¯¯¯
M
F
=
√
(
x
M
−
x
F
)
2
+
(
y
M
−
y
F
)
2

=
√
(
6
−
9
)
2
+
(
6
−
8
)
2
=
√
13
≈
3.6056