Question

Enter the equation of the circle described below.

Center (5, 2), radius = 3

Answer 1

for a circle with center (h,k) and radius, r
the equaiton is

`(x-h)^2+(y-k)^2=r^2`

so

center=(5,2), radius=3


`(x-5)^2+(y-2)^2=3^2`

`(x-5)^2+(y-2)^2=9`

Answer 2

Equation of the circle;

`(x-a)^(2) + (y-b)^(2) = r^(2)`
a=5, b=2 and r= 3

`(x-5)^(2) + (y-2)^(2) = 3^(2)`