asked 90.2k views
5 votes
if a and b are the measures of two first quadrant angles and sin a = 4/5 and sin b = 5/13, find sin a+b.

2 Answers

2 votes

Answer:

[A] sin(a + b) =
(63)/(65)

answered
User Achim
by
8.4k points
7 votes
given that sin a= 4/5
cos a= √(1-sin²a)
= √(1-16/25)
= √(9/25)
= 3/5
sin b=5/13
cos b= √(1-sin²b)
= √(1-25/169)
= √(144/169)
= 12/13

sin(a+b)= sin a· cos b + cos a · sin b
= 4/5· 12/13 + 3/5· 5/13
= 48/65+15/65
= 63/65
hope it helps

answered
User William Xing
by
8.2k points

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