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A line has a slope of -4/5 . Which ordered pairs could be points on a line that is perpendicular to this line? Check all that apply.

(–2, 0) and (2, 5)
(–4, 5) and (4, –5)
(–3, 4) and (2, 0)
(1, –1) and (6, –5)
(2, –1) and (10, 9)

2 Answers

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i hope this helps you
A line has a slope of -4/5 . Which ordered pairs could be points on a line that is-example-1
answered
User Japf
by
8.6k points
4 votes

Answer:

Explanation:

Given that a line has a slope of
(-4)/(5)

For any line perpendicular to this line,

the slope of the line =
(-1)/(slope of the given line) \\=(-1)/((-4)/(5) ) \\=(5)/(4)

Let us check whether the given options satisfy this

a) (-2,0) and (2,5)... slope =
(5-0)/(2-(-2)) =(5)/(4)

Yes true

b) (–4, 5) and (4, –5)... slope =
(-5-5)/(4-(-4)) =(-5)/(4)

No not true.

c) (–3, 4) and (2, 0)

Slope =
(-4)/(5)

No not true.

d) (1, –1) and (6, –5)

Slope =
(-5+1)/(6-1) =(-4)/(5)

No, not true.

e) (2, –1) and (10, 9)

Slope = 5/4

True.

e) (2, –1) and (10, 9)

answered
User Chmodsss
by
8.7k points

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