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1 vote

5= x^(2) +2x

solve the equation using any method you prefer. Give imaginary roots.

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User Yuly
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1 Answer

5 votes

5=x^2+2x\\ x^2+2x-5=0\\ x^2+2x+1-6=0\\ (x+1)^2=6\\ x+1=\sqrt6 \vee x+1=-\sqrt6\\ x=-1+\sqrt6 \vee x=-1-\sqrt6
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User Japboy
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