Question

Solve the compound inequality.

5x + 11 ≥ –9 and 10x – 3 ≤ 27

A. x ≥ –4 and x ≤ 3
B. x ≥ –4 and x ≤ 2 2/5
C. x ≥ 2/5 or x ≤ 2 2/5
D. x ≥ 2/5 or x ≤ 3

Answer 1

5x + 11 ≥ -9 and 10x - 3 ≤ 27
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
x ≥ -4 and x ≤ 3

Answer 2

Thank you for posting your question here, to solve the compound inequality of 5x + 11 ≥ –9 and 10x – 3 ≤ 27 the answer is A which is " x ≥ –4 and x ≤ 3". Below is the solution:

5x + 11 ≥ -9 and 10x - 3 ≤ 27
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
x ≥ -4 and x ≤ 3