A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?

Question

asked Nov 14, 2017 130k views

2 Answers

← Prev Question Next Question →

Ask a Question

NessDan · Answer 1 · 2017-11-21T04:41:48+0000

N = normal force = 38 newtons

Ks = coefficient of static friction = 1.2

Ff = maximum friction force = ks*N = 1.2 * 38 newtons = 45.6 newtons

F = minimum applied force = Ff

F = 45.6 newtons

A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

No related questions found

Categories

Other Questions