Question

How many molecules of liquid methanol are in 10.00 mL of methanol, given its density is 0.7918 g/mL?

Answer 1

`d=0,7918(g)/(mL)\\ V=10mL \ \ \ \ \ \ \ \ \ \ \ m=dV=0,7918(g)/(mL)*10mL=7,918g\\\\ 6,02*10^(23) \ \ \ \ \ \ \ \Rightarrow \ \ \ \ 32g\\ N_(x) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ \ 7,918g\\\\ N_(x)=(6,02*10^(23)*7,918g)/(32g)\approx1,49*10^(23)`