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2 votes
A golf ball is hit with an initial velocity of 155 ft/s at an angle of 23 degrees with the horizontal. After 1.4 seconds, how far has the golf ball traveled horizontally and vertically?. a. 199.7 feet horizontally and 75.2 feet vertically. b. 60.6 feet horizontally and 168.4 feet vertically. c. 199.7 feet horizontally and 53.4 feet vertically. d. 60.6 feet horizontally and 174.4 feet vertically.

1 Answer

3 votes

2) s(t) = 155tcos(23°)
=> s(1.4) = 155 * 1.4 * cos(23°)
=> s(1.4) ≈ 199.7 ft (1 dp) <=- distance displaced horizontally

a(t) = -32 ft/s^2
=> v(t) = -32t + 155sin(23°)
=> h(t) = -16t^2 + 155tsin(23°)
=> h(1.4) = -16(1.4)^2 + 155(1.4)sin(23°)
=> h(1.4) ≈ 53.4 ft (1 dp) <== distance displaced vertically.
answered
User Karns
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