Question

In ∆ABC, if sin A = 4/5 and tan A = 4/3, then what is cos A?

Answer 1

the answer is 3/5 lol hope this helps

Explanation:

Answer 2

In triangle ABC, if
`\sin \angle A>0` and
`\tan\angle A>0,` then
`\cos \angle A>0.`

Use trigonometric formula

`\tan \alpha =(\sin \alpha)/(\cos \alpha)`

to find
`\cos \angle A:`

`\cos \angle A=(\sin \alpha)/(\tan \alpha)=((4)/(5))/((4)/(3))=(3)/(5).`

Answer:
`\cos \angle A=(3)/(5).`