Question

Given the functions j(x) = x2 − 9 and k(x) = −x + 7, which operation results in a 3rd degree polynomial?

Answer 1

No operations...... the other answer is wrong trust me

Answer 2

we have

`j(x) =x^(2)-9\\k(x)=-x+7`

we know that

`j(x)+k(x)` --------> results in a second degree polynomial

`j(x)-k(x)` --------> results in a second degree polynomial

`j(x)*k(x)` --------> results in a third degree polynomial

`j(x)/k(x)` --------> results in a first degree polynomial

so

`j(x)*k(x)`

`(x^(2)-9)*(-x+7)=-x^(3) +7x^(2) +9x-63`

therefore

the answer is

the multiplication of j(x) and k(x)