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If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?

If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
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If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?

asked
User Ventiseis
by
8.0k points

2 Answers

3 votes

Answer:

-1280

Explanation:

just took the test

answered
User Gintautas Miliauskas
by
7.6k points
3 votes
Hello,

f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280

f(n)=160*(-2)^(n-1)


answered
User Huy Tran
by
8.2k points
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