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Tamika had a 4 by 7 in. photograph enlarged. Both length and width were increased to 130% of the original size. Find the perimeter of the enlarged photograph.

Tamika had a 4 by 7 in. photograph enlarged. Both length and width were increased to 130% of the original size. Find the perimeter of the enlarged photograph.
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Tamika had a 4 by 7 in. photograph enlarged. Both length and width were increased to 130% of the original size. Find the perimeter of the enlarged photograph.

asked
User Mohammed Faour
by
7.0k points

1 Answer

1 vote
4*130%=5.2
7*130%=9.1
5.2*2+9.1*2=28.6 in

or You can just do
(4+7)*130%*2=28.6 in
answered
User Fagner Brack
by
8.0k points
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