Question

F(x)= sqare root x-5. find f^1

Answer 1

`f(x)=√(x-5)\\The\ domain\ D_f=x-5\geq0\to x\geq5\\\\y=√(x-5)\ \ \ \ |square\ both\ sides\\\\y^2=x-5\ \ \  \ \ |add\ 5\ to\ both\ sides\\\\x=y^2+5\\\\Answer:\boxed{f^(-1)(x)=x^2+5\ for\ x\in[0;\ \infty)}`