Question

I don't know how to do this

Answer 1

`a_1=2;\ r=-(3)/(2)\\\\a_2=a_1r\to a_2=2\cdot\left(-(3)/(2)\right)=-3\\\\a_3=a_2r\to a_3=-3\cdot\left(-(3)/(2)\right)=(9)/(2)\\\\a_4=a_3r\to a_4=(9)/(2)\cdot\left(-(3)/(2)\right)=-(27)/(4)\\\\a_5=a_4r\to a_5=-(27)/(4)\cdot\left(-(3)/(2)\right)=(81)/(8)`