Which value for x makes the open sentence true? 6 • 7 – 5x + x2 ≥ x3 + x2

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asked Dec 17, 2017 22.7k views

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Paramjeet Singh · Answer 1 · 2017-12-22T04:06:12+0000

6●7–5x+x2≥x3+x2 Lets plug in 3: 6●7–5(3)+32≥33+32 Multiply -5 * 3: 6●7–15+32≥33+32 Simplify all exponents: 6●7–15+9≥27+9 Multiply 6 * 7: 42–15+9≥27+9 Subtract 42 - 15: 27+9≥27+9 Add 27 + 9: 36≥27+9 Add 27 + 9: 36≥36 So 3 is correct.

Which value for x makes the open sentence true? 6 • 7 – 5x + x2 ≥ x3 + x2

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