Question

what is the molality of a solution that is obtained by dissolving 2.922 g of nacl into 1000.0 g of water if the molar mass of nacl is 58.44 g/mol? use molality=moles of solute/kilograms of solvent

Answer 1

1000cm = 1 mol
2.922 g of nacl / 58.44 = 0.05 * 1000 = 50 g/mol

Answer 2

Answer: 0.05 m

Step-by-step explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

`Molality=(n* 1000)/(W_s)`

where,

n = moles of solute

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=(2.922)/(58.44)=0.05moles`

`W_s` = weight of solvent in g=1000 g

Molality =
`(n* 1000)/(W_s)=(0.05* 1000)/(1000)=0.05m`

Thus molality of the solution is 0.05m