Question

The ionic equation for MgCl2 and KOH.

Answer 1

the ionic equation of MgCl2 and KOH are as follows:

MgCl2+KOH

for the we have to multiply by 2 in KOH.

Now,

MgCl2+2KOH --> Mg(OH)2 + 2KCL

Answer 2

The reaction of Mg Cl2 and KOH can be described as a double substitution type of reaction. This means the cations of the reactants are exchanged in places when the products are formed. In this case, the balanced reaction is expressed
MgCl2 (s) + 2KOH (aq) = Mhg (OH)2 (aq) + 2KCl (s)