asked 128k views
3 votes
Jane walked 5.00 meters on a road that inclines 13.0 degrees. How much distance did she cover horizontally?

asked
User PPK
by
8.3k points

2 Answers

5 votes
5*(cos13) Draw the triangle with 5.00 meters as the hypotenuse and 13.0 degrees of the angle that forms to the slope. I hope this helps you :)
answered
User Prashant Sharma
by
7.8k points
0 votes

Answer:

The horizontal distance is 4.54 m.

Step-by-step explanation:

Given that,

Distance = 5 m

Angle =13°

We need to calculate the horizontal distance

According to figure,

Let be the distance x.

Using trigonometry

The horizontal distance is


\cos\theta = (Base)/(Hypotenuse)


\cos13^(\circ)=(x)/(5)


x = 0.907*5


x=4.54\ m

Hence, The horizontal distance is 4.54 m.

Jane walked 5.00 meters on a road that inclines 13.0 degrees. How much distance did-example-1
answered
User MKoosej
by
8.5k points