Question

Organize the following expressions from greatest to least by number of terms: x + 2xyz 3x + y + z 2x2y + x2 − 3x + 4 9x2yz

Answer 1

Expressions

(a) x + 2xyz: two terms

(b) 3x + y + z: three terms

(c) 3x^2 + x^2 - 3x + 4: four terms

(d) 9x^2yz: one term

The order, from greatest to least number of terms is (c), (b), (a) and (d)

Answer 2

Explanation:

The given expressions are:

`x+2xyz`,
`3x+y+z`,
`2x^2y+x^2-3x+4` and
`9x^2yz`.

We have to organize these expressions from greatest to least by number of terms.

The first expression that is
`x+2xyz` has two terms, second expression that is
`3x+y+z` has three terms, third expression that is
`2x^2y+x^2-3x+4` has four terms and the fourth expression that is
`9x^2yz` has one term, thus

Expressions from greatest to least by number of terms are:

`(2x^2y+x^2-3x+4) >(3x+y+z)>(x+2xyz)>(9x^2yz)`