asked 156k views
2 votes
How would you classify a solution if [OH-] = 4.2 x 10-8 M?

2 Answers

4 votes

wrong answer I just took the test

answered
User Yu Fu
by
9.0k points
6 votes
Answer: Slightly acid, almost neutral.

pOH = -log [OH -] = - log [4.2 x 10^-8] = 7.38

pH + pOH = 14 ==> pH = 14 - pOH = 14 - 7.38 = 6.62.

Remember: 7 is neutral, below 7 is acid. This solution is almost neutral.
answered
User Jason Day
by
7.4k points

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