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If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?

If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?
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If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?

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User BrooklynSon
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1 Answer

1 vote
|x|^2 = 13
|x|^2 = 3^2 + b^2 = 9 + b^2

b^2 + 9 = 13

b^2 = 13 - 9

b^2 = 4

b = 2 or - 2
answered
User Chrmue
by
8.4k points
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