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What is the exact value of x in the exponential equation 2^5x − 57 = 43?

What is the exact value of x in the exponential equation 2^5x − 57 = 43?
asked 119k views
3 votes
What is the exact value of x in the exponential equation 2^5x − 57 = 43?

asked
User Zrgiu
by
7.8k points

2 Answers

4 votes

Answer:

The answer according to the test i just took is 2/5log2

Explanation:

answered
User Masad
by
8.6k points
6 votes
Start by getting the term with the exponent on one side

2^(5x)=100

take the log of both sides

log 2^(5x) =log100

There is a log rule that says we can bring down the exponent

5xlog2=log100

Solve for x

5x= (log100)/(log2)
5x=6.64

answer: x=1.33
answered
User Mjwunderlich
by
8.3k points
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