Question

find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule A (n) =-6+(n-1)(6)

Answer 1

a(n) = -6 + (n - 1)(6) = -6 + 6n - 6 = 6n - 12

a(1) = 6(1) - 12 = 6 - 12 = -6

a(4) = 6(4) - 12 = 24 - 12 = 12

a(10) = 6(10) - 12 = 60 - 12 = 48

Answer 2

Answer with explanation:

General term of arithmetic sequence and first, fourth, and tenth terms are

`A_(n)=-6 +6(n-1)\\\\A_(1)= -6 +6(1-1)\\\\A_(1)=-6\\\\A_(4)=-6+6(4-1)\\\\A_(4)=-6+6 * 3\\\\A_(4)=-6+18\\\\A_(4)=12\\\\A_(10)=-6+6 * (10-1)\\\\A_(10)=-6+6 *9\\\\A_(10)=-6+54\\\\A_(10)=48`