asked 31.5k views
1 vote
A 12-ft-by-15-ft rectangular swimming pool has a 3-ft-wide no-slip surface around it. What is the outer perimeter of the no-slip surface? a. 78 ft. b. 78 ft2. c. 198 ft. d. 198 ft2

asked
User Haukman
by
8.2k points

2 Answers

0 votes

Answer:

a. 78 ft

Explanation:

First calculate the length and width of the rectangle around the swimming pool.

Length:
15+3+3=21ft

Width:
12+3+3=18ft

The circumference is the sum of 2 times the length and 2 times the width:


C=(2*l)+(2*w)\\C=(2*21)+(2*18)\\C=42+36\\C=78ft

5 votes
we are given with a swimming pool with dimensions
12-ft-by-15-ft. given that there is a 3-ft-wide no-slip surface around it, the new dimensions now become (12+3+3) or 18 ft by (15+3+3) or equal to 21 ft. The perimeter is the sum of the sides of the new rectangle. Perimeter is equal to 18+ 18 + 21 + 21 or equal to 78 feet
answered
User Shanoah
by
7.9k points
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