Question

Can someone show me the work for this?

Suppose y = sqrt (2x + 1) where x and y are functions of t.?

suppose y = sqrt (2x + 1) ,where x and y are functions of t.

(a) If dx/dt = 3, find dy/dt when x = 4.
dy / dt = ?

(b) If dy/dt = 5, find dx/dt when x = 12.
dx/dt= ?

Answer 1

we are given the equation or function y = sqrt (2x + 1). The derivative of the equation is expressed as

1. dy/dt = 0.5 *2 *(2x + 1)^-0.5 dx/dt
when x = 4 and dx/dt =3
dy/dt = 0.5 *2 *3*(2*4 + 1)^-0.5
dy/dt = 1

2. dy/dt = 0.5 *2 *(2x + 1)^-0.5 dx/dt
If dy/dt = 5, find dx/dt when x = 12.
5= 0.5 *2 (2*12 + 1)^-0.5 dx/dt
dx/dt = 1