Question

I have no clue how to do this...

Answer 1

`\log16x^2+2\log(1)/(x)=\log(4x)^2+2\log(1)/(x)=2\log4x+2\log(1)/(x)\\\\=2\left(\log4x+\log(1)/(x)\right)=2\log\left(4x\cdot(1)/(x)\right)=2\log4=\log4^2=\boxed{\log16}`