asked 22.7k views
1 vote
identify the oblique asymptote of f(x) = quantity x squared minus 4 x plus 8 over quantity x plus 2. y = 0 y = x - 2 y = x - 6 no oblique asymptote

asked
User MBober
by
8.2k points

2 Answers

3 votes

Answer:

Oblique asymptote is y= x- 6

Explanation:

f(x)=
(x^2-4x+8)/(x+2)

To find out ablique asymptote we use long division

x - 6

------------------------------

x+2 x^2- 4x+ 8

x^2+ 2x

------------------------------ (Subtract it )

- 6x + 8

- 6x - 12

------------------------------(Subtract it)

-20

Quotient is the oblique asymptote

Oblique asymptote is y= x- 6

answered
User Souki
by
7.4k points
5 votes
Using long division, f(x) = x - 6 remainder 20
Therefore, oblique asymptote is y = x - 6
answered
User Ghasem Pahlavan
by
8.9k points
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