Question

Someone help please? :(

What is the equation in point-slope form of the line passing through (−2, 1) and (4, 13)?

y − 1 = −2(x − 4)

y − 1 = 2(x + 2)

y − 13 = −2(x + 2)

y − 13 = 2(x + 4)

Answer 1

(-2,1)(4,13)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (13 - 1) / (4 - (-2)
slope(m) = 12/6 = 2

y - y1 = m(x - x1)
slope(m) = 2
(-2,1)...x1 = -2 and y1 = 1
now we sub
y - 1 = 2(x - (-2)
y - 1 = 2(x + 2) <=== ur answer

Answer 2

The equation in point-slope form of the line passing through (−2, 1) and (4, 13)would be y - 1 = 2(x+2). The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query about and it will be able to help you.