Question

solve for x 4x^2=-20x-25 if there is more than one solution, separate them with commas. if there is no solution, click on "no solution."

Answer 1

`4 x^(2) +20x+25=0`

`a x^(2) +bx+c=0`
Δ=
`b^(2) -4ac`
Δ=
`20^(2) - 4*4*25`
Δ=400 - 400 = 0

if
Δ > 0 equation has 2 solution
Δ = 0 equation has 1 solution
Δ < 0 no real solution


`x= (-b)/(2a)`


`x_(0) = (-20)/(2*4) = (-20)/(8) = -2.5`