Question

Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), Hf = –296.8 kJ/mol) according to the equation below.

What is the enthalpy change for the reaction?
Use

Answer 1

-296.8

Step-by-step explanation:

Answer 2

We want:

S(s) + O2(g) --> SO2(g)

given

1) S(s) + 3/2O2(g) --> SO3(g) ∆H = -395.8 kJ/mole

2) 2SO2 + O2 --> 2SO3(g) ∆H = -198.2 kJ/mole

Reverse Equation 2) and divide by 2

SO3(g) --> SO2(s) + 1/2O2(g) ∆H = +99.1 kJ/mole

Add Equation 1)

S(s) + O2(g) --> SO2(g) ∆H = -296.7 kJ/mole