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1 vote
Find cube of
a)-0.16
b)-2/7
c)14

1 Answer

3 votes
a)
(-0.16)^3 = (-0.16)\cdot(-0.16)\cdot (-0.16) = -(16)/(100)\cdot(16)/(100)\cdot(16)/(100)=

= -(16^3)/(100^3) = -(2^(12))/(10^6) = -(4\cdot 2^(10))/(10^6) = -(4096)/(1000000) = -0.004096

b)
\left(-(2)/(7)\right)^3 = -(2^3)/(7^3) = -(8)/(343)

c)
14^3 = (2\cdot 7)^3 = 2^3\cdot 7^3 = 8\cdot 343 = 2744
answered
User Quetzaluz
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